(2x-5)(x-3) - (3x+2)(3-x) factorisation (3x-5)2 - (x+2)2
Mathématiques
lovely0girl
Question
(2x-5)(x-3) - (3x+2)(3-x) factorisation (3x-5)2 - (x+2)2
2 Réponse
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1. Réponse Anonyme
[tex](2x-5)(x-3)-(3x+2)(3-x)=(2x-5)(x-3)+(3x+2)(x-3)[/tex]
[tex](2x-5)(x-3)+(3x+2)(x-3)=(x-3)(5x-3)[/tex]
[tex](3x-5)^2-(x+2)2=(3x-5-x-2)(3x-5+x+2)[/tex]
[tex](3x-5-x-2)(3x-5+x+2)=(2x-7)(4x-3)[/tex] -
2. Réponse Miky93
[tex](2x-5)(x-3)-(3x+2)(3-x)= \\\\ = (2x-5)(x-3)-[-(3x+2)(x-3)]= \\\\ =(2x-5)(x-3)+(3x+2)(x-3)= \\\\ =(x-3)[(2x-5)+(3x+2)]= \\\\ = (x-3)(2x-5+3x+2)=\\\\ = \boxed{(x-3)(5x-3)}[/tex]
[tex](3x-5)^2-(x+2)^2= \\\\ =[(3x-5)-(x+2)][(3x-5)+(x+2)]= \\\\ =(3x-5-x-2)(3x-5+x+2)= \\\\ =\boxed{(2x-7)(4x-3)}[/tex]