Faire les factorisations: (3x-5)² - 4(3x-5) (7x+3) (x-2) + (7x+3)² (-x+1) (2x+1) - (2x+1) (x-10) (3x-8) (x-2) + (5x+7) (3x-8) 3(x-4) - (x+2) (x-4)
Mathématiques
chacha2783
Question
Faire les factorisations:
(3x-5)² - 4(3x-5)
(7x+3) (x-2) + (7x+3)²
(-x+1) (2x+1) - (2x+1) (x-10)
(3x-8) (x-2) + (5x+7) (3x-8)
3(x-4) - (x+2) (x-4)
(3x-5)² - 4(3x-5)
(7x+3) (x-2) + (7x+3)²
(-x+1) (2x+1) - (2x+1) (x-10)
(3x-8) (x-2) + (5x+7) (3x-8)
3(x-4) - (x+2) (x-4)
1 Réponse
-
1. Réponse jess3
1)=(3x-5)[3x-5)-4]
(3x-5)(3x-5-4)
(3x-5)(3x-9)
2)=(7x+3)[(x-2)+(7x+3)]
(7x+3)(x-2+7x+3)
(7x+3)(8x+1)
3)=2x+1[(-x+1)-(x-10)]
(2x+1)[-x+1-x+10)
(2x+1)(-2x+11)
4)=(3x+8)[(x-2)+(5x+7)
(3x-8)(x-2+5x+7)
(3x-8)(6x+5)
5)=(x-4)[3-(x+2)]
(x-4)(3-x-2)
(x-4)(-x+1)