factorises a=(2x+1)(x+2)-(2-x)(x+3) b=9x²-4+(6x-8)
Mathématiques
aountidjani12
Question
factorises
a=(2x+1)(x+2)-(2-x)(x+3)
b=9x²-4+(6x-8)
a=(2x+1)(x+2)-(2-x)(x+3)
b=9x²-4+(6x-8)
1 Réponse
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1. Réponse Wunder
a=(2x+1)(x+2)-(2-x)(x+3)
=((2*x+1)*(x+2)-(2-x)*(x+3))
[tex]=3*(-(-3-sqrt(21))/3+x) * (-(-3+sqrt(21))/3+x) [/tex]
=3*(2.5275252316519+x)*(-0.52752523165193+x)
b=(9x²-4+(6x-8))
=(9*x^2-4+6*x-8)
=[tex]9*(-(-1-sqrt(13))/3+x)*(-(-1+sqrt(13))/3+x)[/tex]
=9*(1.535183758488+x)*(-0.86851709182133+x)