factoriser (2x+5) (x-1)-8(x-1)
Mathématiques
jkj
Question
factoriser (2x+5) (x-1)-8(x-1)
2 Réponse
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1. Réponse nonotata
(2x+5) (x-1)-8(x-1)
(x-1)(2x+5-8)
(x-1)(2x-3) -
2. Réponse Wunder
(2x+5) (x-1)-8(x-1)= ((2*x+5)*(x-1)-8*(x-1))
= (x-1)*(-3+2*x)