qqun peut me faire ca: (5x+1)/6 < (3x-3)/8

[tex]\frac{5x+1}{6}^{(8}}< \frac{3x-3}{8}^{(6} \\\\ 40x+8<18x-18 \\\\ 40x-18x<-18-8 \\\\ 22x<-26 \ \ \ |:2 \\\\ 11x<-13 \\\\ x<-\frac{13}{11} \\\\ \boxed{ x \in (-\infty; -\frac{13}{11})}[/tex]