Mathématiques

Question

aider moi svp

developer reduire ordoner

a:(3x+7)(4x+3)-(5x+2)
b:2x-4(2x-5)-(2x+9)
c:4x-3+7x-4+9x
d:(2x-3)-(6x+3)-4x
e:(3x-2)(5x+3)-(2x+7)
f:9(3x+4)(5x-9)
g:2x(4x-2)-(4x+7)
h:(3x-1)(3x+1

1 Réponse

  • Développer, réduire et ordonner

    a:(3x+7)(4x+3)-(5x+2)
    = 12x² + 9x + 28x + 21 - 5x - 2
    = 12x² + 9x + 28x - 5x + 21 - 2
    = 12x² + 32x + 19

    b:2x-4(2x-5)-(2x+9)
    = 2x - 8x + 20 - 2x - 9
    = 2x - 8x - 2x + 20 - 9
    = - 8x + 11

    c:4x-3+7x-4+9x
    = 4x + 7x + 9x - 3 - 4
    = 20x - 7

    d:(2x-3)-(6x+3)-4x
    = 2x - 3 - 6x - 3 - 4x
    = 2x - 6x - 4x - 3 - 3
    = - 8x - 6

    e:(3x-2)(5x+3)-(2x+7)
    = 15x² + 9x - 10x - 6 - 2x - 7
    = 15x² + 9x - 10x - 2x - 6 - 7
    = 15x² - 3x - 13

    f:9(3x+4)(5x-9)
    = 9 (15x² - 27x + 20x - 36)
    = 135x² - 162x + 180x - 324
    = 135x² + 18x - 324

    g:2x(4x-2)-(4x+7)
    = 8x² - 4x - 4x - 7
    = 8x² - 8x - 7

    h:(3x-1)(3x+1)
    = 9x² + 3x - 3x - 1
    = 9x² - 1

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