qqun peut me résoudre ces inéquation -8+5x<3x-4 et 19+7x>-2+4x

-8+5x<3x-4
= 5x-3x< -4+8
= 2x< 4
= x< 4/2
= x< 2


19+7x>-2+4x
= 7x-4x>-2-19
=3x>-21
=x>-21/3
=x>-7

[tex]-8+5x\ \textless \ 3x-4 \\\\ 5x-3x\ \textless \ -4+8 \\\\ 2x\ \textless \ 4 \ \ \ \ |:2 \\\\ x\ \textless \ 2 \\\\ \boxed{x \in (-\infty; 2)} \\\\\\ 19+7x\ \textgreater \ -2+4x \\\\ 7x-4x\ \textgreater \ -2-19 \\\\ 3x\ \textgreater \ -21 \ \ \ |:3 \\\\ x\ \textgreater \ -7 \\\\ \boxed{ x \in (-7; \infty)}[/tex]