Mathématiques

Question

AIDE SVPL POUR DEMAIN

RESOUDRE les equations suivantes ;

(5x+12)(5-2x)+(3x-3)=0
(2x-8)(5+5x)-(6x-13)(2x-8)=0
(5+3x)² - (5+3x)(x-7)=0
(2x-4)² -9=0


MERCI BEAUCOUP DE L'aide

1 Réponse

  • (5x+12)(5-2x)+(3x-3)=0
    ??


    (2x-8)(5+5x)-(6x-13)(2x-8)=0
    (2x-8)(5+5x-6x+13) =0
    (2x-8)(-x+18) =0

    2x-8 =0           -x+18 =0
    2x =8               -x = -18
    x = 8/2 = 4          x = 18


    (5+3x)² - (5+3x)(x-7)=0
    (5+3x)(5+3x-x+7) =0
    (5+3x)(2x+12) =0

    5+3x =0                      2x+12 =0
    3x = -5                            2x = -12
    x = -5/3                            x = -12/2 = -6


    (2x-4)² -9=0
    (2x-4)² -3² =0
    (2x-4-3)(2x-4+3) =0
    (2x-7)(2x-1) =0

    2x-7 =0                     2x+1 =0
    2x = 7                             2x = -1
    x = 7/2                             x = -1/2


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